Question

Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . NaOH(aq). Calculate the amount of Ga ( s ) Ga(s) that can be deposited from a Ga ( III ) Ga(III) solution using a current of 0.880 A 0.880 A that flows for 30.0 min .

Answer 1

0.382 g

Step-by-step explanation:

Let's consider the reduction of gallium (III) to gallium that occurs in the electrolysis.

Ga³⁺ + 3 e⁻ → Ga

We can establish the following relations:

• 1 minute = 60 second
• 1 Ampere = 1 Coulomb / second
• The charge of 1 mole of electrons is 96,468 Coulomb (Faraday's constant)
• 1 mole of gallium is deposited when 3 moles of electrons circulate.
• The molar mass of gallium is 69.72 g/mol

We will use this that to determine the mass of gallium deposited from a Ga(III) solution using a current of 0.880 A that flows for 30.0 min

`30.0min * (60s)/(1min) * (0.880c)/(s) * (1mole^(-) )/(96,468c) * (1molGa)/(3 mole^(-)) * (69.72g)/(1molGa) = 0.382 g`