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A 70.0-kilogram man is walking at a speed of 2.0 m/s. What is his kinetic energy?

User Klepto
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1 Answer

5 votes

KE : 1/2mv^2

KE: 1/2 x 70(2^2)

KE: 1/2 x 70 x 4

= 1/2 x 280

280 x 1/2 = 140

Therefore, the man's kinetic energy is 140J.

User Geovanni
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