Question

3x-5=-2x^2select the two values of x that are roots of this equation

Answer 1

The two solutions for x are:

`- (5)/(2)`

and

`1`

Explanation:

Order and solve the quadratic:

`3x - 5 = - 2{x}^(2) \\ 2 {x}^(2) + 3x - 5 = 0 \\ 2 {x}^(2) - 2x + 5x - 5 = 0 \\ 2x(x - 1) + 5(x - 1) = 0 \\ (2x + 5)(x - 1) = 0 \\ \\ 2x + 5 = 0 \\ 2x = - 5 \\ x = - (5)/(2) \\ \\ x - 1 = 0 \\ x = 1`