Question

At what temperature will 0.0705 mol of Cl2 exert a pressure of 900. torr at a volume of 0.750L? Round to 3 sig figs

Answer 1

Answer : The temperature
`Cl_2` gas is, 153 K

Explanation :

Using ideal gas equation:

`PV=nRT`

where,

P = Pressure of
`Cl_2` gas = 900 torr = 1.18 atm (1 atm = 760 torr)

V = Volume of
`Cl_2` gas = 0.750 L

n = number of moles
`Cl_2` = 0.0705 mole

R = Gas constant =
`0.0821L.atm/mol.K`

T = Temperature of
`Cl_2` gas = ?

Putting values in above equation, we get:

`1.18atm* 0.750L=0.0705mole* (0.0821L.atm/mol.K)* T`

`T=152.9K\approx 153K`

Therefore, the temperature
`Cl_2` gas is, 153 K