Question

A spinner is split into 4 equal parts labeled 1, 2, 3, and 4.

What is the probability of landing on an even number? (Write your final answer as a percentage.)



P(event) =

Answer 1

A spinner is split into 4 equal parts labeled 1, 2, 3, and 4.

What is the probability of landing on an even number? (Write your final answer as a percentage.)

ANSWER:

P(event) = 50%

Explanation:

just took on EDGE 2020 hope it helps.

:)

Answer 2

50%

Explanation:

If there are 4 parts to the spinner, 4 is the whole. Since there are 2 even numbers (2&4), the fraction would be
`(2)/(4)`, which is simplified to
`(1)/(2)`. And because
`(1)/(2)` could also turn into
`(50)/(100)`, the percentage is 50%.

Hope this helps :)