Answer:
There are 5 adults and 15 children in the family.
Explanation:
Given
Number of people in the family = 20
Cost of adults tickets = $8
Cost of children tickets = $4
Total ticket sold = $100
Required
How many adults and children are in the family.
Let C represent children and A represent adults.
If there are 20 members of the family, then.
A + C = 20
Also, if adult tickets is sold for $8 and children tickets is sold for $4 and the total cost of tickets were $100, then we have
8A + 4C = 100.
Now, we have two equations to be solved simultaneously.
A + C = 20 --- (1)
8A + 4C = 100 ---- (2)
Make C the subject of formula in (1)
C = 20 - A.
Substituton 20 - A for C in (2)
8A + 4(20 - A) = 100
8A + 80 - 4A = 100
Collect like terms
8A - 4A = 100 - 80
4A = 20
Multiply both sides by ¼
¼ * 4A = ¼ * 20
A = 5
Recall that C = 20 - A
So,
C ,= 20 - 5
C = 15.
Hence, there are 5 adults and 15 children in the family.
The Question was solved by getting an expression to represent the amount of tickets that were sold and another expression for the total number of people in the family.
The two expressions gave us a simultaneous equation and the equations were solved simultaneously.