Answer: D.
Explanation:
First, find the area of the two squares:
The photograph: (-3, -2), (-2, 2), (2, 1), and (1, -3).
The square is diagonally aligned, so we need to find the length between two points in order to find the area.
I will use (1, -3) and (2, 1).
There is a 1 unit length and a 4 unit height. We can use the Pythagorean theorem to find the hypotenuse of the triangle, which is the length of the square's side:
1^2 + 4^2 = x^2
1 + 16 = x^2
x = square root of 17
The side length for the square of the photograph is the square root of 17, so the area of the photograph is 17 units^2.
The red paper has side lengths of 8. The distance between (-4, 4) and (4, 4) is 8 units wide, so we do not need to use the Pythagorean theorem.
Now that we know the area of the red paper and photograph, you can subtract the area to find the red paper with the hole:
64 - 17 = 47 square units.