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4 votes
Solve the system of equations:
y=2x-3
y=x2-3

User Bobby Dore
by
6.7k points

1 Answer

5 votes

Answer: x = 0 or x = 2

Explanation:

To solve this, we must note that the two equations speaks of a single function of y. So

y = 2x - 3 = x² - 3

So from.here we can equate the two together and solve for x.

x² - 3 = 2x - 3, biw convert to a quadratic expression

x² - 2x - 3 + 3 = 0

x² - 2x = 0

Now factorize

x( x - 2 ) = 0, so solving for x

x = 0 or x = 2. .I believed getting the 2 won't be a problem

When x - 2 = 0

Then x = 2.

User AticusFinch
by
5.6k points