Answer: The carbon-14 left after 10 years is 25 g
Step-by-step explanation:
Expression for rate law for first order kinetics is given by:
![t=(2.303)/(k)\log(a)/(a-x)](https://img.qammunity.org/2021/formulas/physics/high-school/34336uhzgbxxst4voy5o2jexos3nnuq6xo.png)
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for rate constant
![t_{(1)/(2)}=(0.693)/(k)](https://img.qammunity.org/2021/formulas/chemistry/college/kof3tg7uw2qdyjru3ryq963s91ahnvldt3.png)
![k=(0.693)/(5years)=0.139years^(-1)](https://img.qammunity.org/2021/formulas/chemistry/college/vwzs6djy12ywg76agxup4t6z0qew0ldka6.png)
b) for amount left after 10 years
![t=(2.303)/(k)\log(a)/((a-x))](https://img.qammunity.org/2021/formulas/chemistry/college/m1hw6uimqdg7v3i2xcsyoff64ckxhfze93.png)
![10=(2.303)/(0.139)\log(100)/((a-x))](https://img.qammunity.org/2021/formulas/chemistry/college/i7ac7eouebywww7ypz1s7gtzrx5figncvo.png)
![(a-x)=25g](https://img.qammunity.org/2021/formulas/chemistry/college/kmow0q7s8gsm1wimn5k8a1lrvw58cosvy4.png)
Thus carbon-14 left after 10 years is 25 g