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How many moles of SnF₂ will be produced along with 48 grams of H₂? *

Sn + 2HF (arrow) SnF2 + H2

12 moles
24 moles
48 moles
96 moles

User Bryan A
by
6.0k points

1 Answer

2 votes

Answer: 24 moles of
SnF_2 are produced.

Step-by-step explanation:

To calculate the moles :


\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}


{\text{Moles of} H_2}=(48g)/(2g/mol)=24moles


Sn+2HF\rightarrow SnF_2+H_2

According to stoichiometry :

1 mole of
H_2 is accompanied with = 1 mole of
SnF_2

Thus 24 moles of
H_2 is accompanied with =
(1)/(1)* 24=24moles of
SnF_2

Thus 24 moles of
SnF_2 are produced.

User Crysxd
by
5.3k points