Question

An open organ pipe is 2.46 m long, and the speed of the air in the pipe is 345 m/s.

a. What is the fundamental frequency of this pipe?

Answer 1

Fundamental frequency is 70.12 m

Step-by-step explanation:

For an open organ pipe, the fundamental frequency is given by :

`f=(nv)/(2l)`

n = 1 for fundamental frequency

v is speed of sound in air, v = 345 m/s

l is length of open organ pipe, l = 2.46 m

Substituting values in above formula. So,

`f=(1* 345)/(2* 2.46)\\\\f=70.12\ Hz`

So, the fundamental frequency of this pipe is 70.12 m.