Question

3. A 0.35 kg puck slides across the ice with an average force of friction of 0.15 N acting on it. It slides 82 m before coming to rest. How much work was done on the puck?

Answer 1

Work done is 12.3 J

Step-by-step explanation:

We have,

Mass of puck, m = 0.35 kg

Force of friction acting on the puck when it slides is 0.15 N

Distance travelled by the puck is 82 m.

It is required to find the work done on the puck. Finally the puck comes to rest and the force of friction is acting on it. It means the applied force is 0.15 N. Work done is given by

`W=Fd\\\\W=0.15* 82\\\\W=12.3\ J`

The work done on the puck is 12.3 J.