1 Answer

WayFarer · Answer 1 · 2021-08-21T23:37:23+0000

Answer:

(1)/(2) ( cos40° + isin40°)

Explanation:

To divide

$\frac{r_{1(cosx_(1)+isinx_(1)) } }{r_(2)(cosx_(2)+isinx_(2)) }$

=
(r_(1) )/(r_(2) ) [ cos(x₁ - x₂) + isin(x₁ - x₂)

Given

(2(cos90+isin90)/(4(cos50+isin50))

=
(2)/(4) ( cos(90 - 50)° + isin(90 - 50)°

=
(1)/(2) ( cos40° + isin40° )

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