Solve S= 2ab + 2bc + 2ac for b. A) s-4a/c B) s/2(a+c) C) s/a+b+c D) s-2ac/2a+2c

asked Sep 16, 2021 163k views

3 votes

Solve S= 2ab + 2bc + 2ac for b.

A) s-4a/c

B) s/2(a+c)

C) s/a+b+c

D) s-2ac/2a+2c

4.4k points

Please log in or register to add a comment.

4 votes

Answer:

D) s-2ac/2a+2c

Explanation:

$s = 2ab + 2bc + 2ac \\ s - 2ac = b(2a + 2c) \\ \huge \red{ \boxed{ b = (s - 2ac)/(2a + 2c) }}$

Hammas answered Sep 21, 2021

4.3k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.5m questions

5.8m answers