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A student was given the equation x^2+2x-16=0 to solve by completing the square. The first step that was written is shown below. ——> X^2 + 2x=16<—— The next step in the student’s process was x^2 +2x+c =16+c. State the value of c that creates a perfect square trinomial.

User KDecker
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Answer:


x_(1)=-1+√(17),\:x_(2)=-1-√(17)

Explanation:

Quadratic Equation Given:


x^2+2x-16=0


x^2 + 2x=16


$c=\left( (b)/(2) \right)^2 $


x^2 + 2x+1=16+1


(x+1)^2=17\\


x+1=\pm √(17) \\


x=-1 \pm √(17) \\


x_(1)=-1+√(17),\:x_(2)=-1-√(17)

User Vladimir Prudnikov
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