Question

How much force is required to produce a torque of 100 Nm if the force is applied at an angle of 40 at a distance of 25 cm from the pivot?

Answer 1

Force, F = 622.28 N

Step-by-step explanation:

It is given that,

Torque,
`\tau=100\ N-m`

Angle between force and displacement,
`\theta=40^(\circ)`

Distance, d = 25 cm = 0.25 m

We need to find the force required to produce the torque. Torque produced by an object is given by :

`\tau=Fd\sin\theta`

F is force required to produce torque

`F=(\tau)/(d\sin\theta)\\\\F=(100)/(0.25* \sin(40))\\\\F=622.28\ N`

So, applied force is 622.28 N.