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(2y+3)( 3y² +4y+5)
What’s the product?

User Tanzio
by
4.2k points

2 Answers

3 votes

Answer:

6y³ + 17y² + 22y + 15

Explanation:

(2y+3) ( 3y² +4y+5)

Keep the 'FOIL' method (first, outside, inside, last) when distributing and you'll end up with

(2y)(3y² ) + (2y)(4y) +(2y)(5 ) +(3)(3y2) + (3)(4y) + (3)(5)

Now, multiply each set to get

6y³+8y²+10y+9y²+12y+15

From there, just simplify/combine like terms (8y² + 9y² and 10y + 12y) to get your final answer: 6y³ + 17y² + 22y + 15

User FTWynn
by
4.2k points
3 votes

Answer:

6y3+17y2+22y+15

Explanation:

User Ljetibo
by
4.3k points