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What is the maximum height for -16t^2+96t+63

User Frayal
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1 Answer

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Answer:

h(3) = 207 feet

Explanation:

what is the maximum height for -16t^2+96t+63

h(t) = -16t^2+96t+63

We see max height at the vertex of this parabolic function

x = -96/2*(-16) = 3 seconds

h(3) = -16*3*3 + 96*3 + 63

h(3) = -144 + 288 + 63

h(3) = 207 feet

User Amozoss
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