Question

A dart is tossed and hits the dart board shown.

The dart is equally likely to land on any point on
the dart board. Find the probability, as a percent
to the nearest tenth, that the dart lands in the
ring surrounding the bullseye.

Answer 1

The probability that dart lands on ring surrounding bull eye to the nearest tenth is: 4.9%

Area of ring surrounding bulleye :

• πr² ; r = 2 in

Area = π×2² = 12.56 in²

Total area of dart board :

• Area of square = s²

Area = 16² = 256

The probability of dart landing in ring surrounding bull eye :

• 12.56 / 256 = 0.004906

Expressing as a percentage:

• 0.004906 × 100% = 4.9%

Answer 2

4.9%

Explanation:

To find the probability of the dart hitting the red circle, we need to find the total area of the board and the area of the red circle.

The area of the board is 16 in * 16 in = 256 in2

The area of the red circle is pi * 2^2 = 12.5664 in2

So the probability of the dart landing on the red circle is:

Probability = area_circle / area_board = 12.5664 / 256 = 0.0491 = 4.91%

Rounding to nearest tenth, we have 4.9%