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Yet another variation: A better packet switched network employs the concept of acknowledgment. When the end user’s device receives a packet correctly it sends an acknowledgment to the sender. Here too, a packet is received correctly with probability p, but the sender keeps sending copies of a given packet until a copy is correctly received (signaled by acknowledgment). Let random variable N be the number of times the same message packet is sent. a) Find the PMF PN (n).

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Answer:

P(N = n) =
(1-P)^(n-1) * P

Explanation:

to find out

Find the PMF PN (n)

solution

PN (n)

here N is random variable

and n is the number of times

so here N random variable is denote by the same package that is N (P)

so here

probability of N is

P(N ) = Ф ( N = n) .................. 1

here n is = 1, 2,3, 4,...................... and so on

so that here P(N = n) will be

P(N = n) =
(1-P)^(n-1) * P

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