Answer:
Step-by-step explanation:
λ
given λ = 700 nm
a) for first maxima, d*sin(θ) = λ
sin(theta) = λ/d
= 700*10^-9/(0.025*10^-3)
= 0.028
theta θ = sin^-1(0.028)
= 1.60 degrees
b) given R = 1 m,
delta_y = λ*R/d
= 700*10^-9*1/(0.025*10^-3)
= 0.028 m or 2.8 cm
c) for first maxima, d*sin(θ) = λ
sin(θ) = λ/d
= 700*10^-9/(2.5*10^-3)
= 0.00028
theta = sin^-1(0.00028)
= 0.0160 degrees
d) R = 25 mm = 0.025 m
δ_y = λ*R/d
= 700*10^-9*0.025/(2.5*10^-3)
= 7*10^-6 m or 7 micro m
e) No. But the position of maxima and minima will be shifted.