Answer:
Optimal production quantity = 2970
Explanation:
As per the data given in the question,
Cost of card (c) = $0.10 + $0.42 = $0.52
Selling price (p) = $2.40
Salvage value (v) = 0
So,Critical ratio (Z)
= (p - c) ÷ (p - v)
= ($2.40 - $0.52) ÷ ($2.40 - 0)
=0.7833
Z(0.7833) = NORMSINV (0.7833)
Z(0.7833) = 0.783387
n = no. of city = 1
μ = n × mean demand = 1 × 2,500 = 2,500
Optimal production quantity = μ + Z (0.7833) × standard deviation
= 2,500 + 0.783387 × 600
= 2970.03
= 2970
We simply applied the above formula