Answer:
James has 20 more coins than Reggie
Explanation:
Given:
Total number of coins with James and Reggie = 60
If James would agree to give 1/4 of his coins to Reggie, they would then have exactly the same number of coins
To find: number of coins with James and Reggie
Solution:
Let x denote number of coins with James and y denote number of coins with Reggie.
According to question,
![x+y=60\\x-(x)/(4) =y+(x)/(4) \\x-y=(2x)/(4) \\x=2y](https://img.qammunity.org/2021/formulas/mathematics/high-school/yjcqs6nb5stivdapywkv4za96dlghgfcsq.png)
Put
in
![x+y=60](https://img.qammunity.org/2021/formulas/mathematics/high-school/s6ldzoo9od22uq6sqgl30tczhhas18zg1b.png)
![2y+y=60\\3y=60\\y=(60)/(3)=20\\ x=2y=2(20)=40](https://img.qammunity.org/2021/formulas/mathematics/high-school/68pqzt0uwocitg5f2z5op0pph1waoi6o8p.png)
So,
number of coins with James = 40
number of coins with Reggie = 20
James has 20 more coins than Reggie