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Y={2x-1)(x+4)(2x-3)(x-1)

User Samnau
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1 Answer

13 votes
13 votes

Answer:

Y =4x^4 + 4x^3 − 37x^2 + 41x −12

Explanation:

Y = (2x - 1 ) (x + 4) (2x - 3) (x - 1)

Using commutative property we can re-arrange RHS,

Y= (2x - 1) (2x - 3) (x + 4) (x - 1)

Using the property

[(x+a) (x+b) = x^2 + (a+b)*x +ab],

Y =

[(2x)^2 + (-1 - 3)*2x + (-1 )*(-3)] [x^2 + (4 - 1)*x + 4*(-1)]

From here onwards I would recommend u to do the calculation by your own bc I might have made mistakes

in the steps but I got right but still just check yourself if u copy all the steps as it is

Y = (4x^2 -8x + 3) (x^2 + 3x -4)

Y = 4x^4 + 12x^3 - 16x^2 -8x^3 -24x^2 + 32x + 3x^2 + 9x - 12

Y = 4x^4 + 4x^3 -37x^2 + 41x - 12

Here I got the answer right so my calculations will also might be right

I checked my answer if it's right using an app called "MathPapa" and it's a great app to solve algebra questions like urs. The screenshot of the answer using this app is here on the top. This is the longest question I have solved for anyone, bye and have a nice day ahead!

Y={2x-1)(x+4)(2x-3)(x-1)-example-1
User Alexander Bily
by
2.8k points