Answer:
(a)Time taken to reach the ground, x=6 seconds
(b)Maximum height of the arrow during its flight =101.25 feet
Explanation:
Given the quadratic function which models the flight of the arrow:
![y=-5x^2+15x+90](https://img.qammunity.org/2021/formulas/mathematics/middle-school/k5zpnk3simmyl4j02muen3a4mtx9je9hgv.png)
Where:
- y represents the vertical height of the arrow, in meters; and
- x represents the time, in seconds.
(a)Positive Zero
![-5x^2+15x+90=0\\-5(x^2-3x-18)=0\\-5(x^2-6x+3x-18)=0\\-5(x(x-6)+3(x-6))=0\\-5(x+3)(x-6)=0\\x+3=0\:or\:x-6=0\\x=-3,x=6](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mb9lr74jo3hbvjdaydooztnignytleca61.png)
In 6 seconds, the arrow will hit the horizontal plane, i.e. the ground.
(b)
![y=-5x^2+15x+90\\y-90=-5(x^2-3x)\\y-90-5((9)/(4)) =-5(x^2-3x+((3)/(2) )^2)\\y-101.25=-5(x-(3)/(2) )^2\\y=-5(x-(3)/(2) )^2+101.25](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mcoetnmc437skmifphv5ohnhdse2nxd05b.png)
Comparing with the vertex form:
![y=a(x-h)^2+k](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8p1sxsgegitwlyo0h3hri0gwrs8yt9xyxk.png)
Our vertex, (h,k)=(1.5, 101.25)
Maximum Value of y=101.25
The maximum value of y represents the maximum height of the arrow during its flight, which is 101.25 feet.