Answer:
0.169M
Step-by-step explanation:
The following were obtained from the question:
Mass of sucrose (C12H22O11) = 55g
Volume of solution = 950 mL
Next, we shall determine the number of mole of sucrose in 55g of sucrose. This is illustrated below:
Mass of C12H22O11 = 55g
Molar Mass of C12H22O11 = (12x12) + (22x1) + (16x11) = 144 + 22 + 176 = 342g/mol
Number of mole = Mass/Molar Mass
Number of mole C12H22O11 = 55/342 = 0.161 mole
Next, we shall convert 950 mL to L. This is illustrated below:
1000mL = 1L
Therefore, 950mL = 950/1000 = 0.95L
Now, we can calculate the molarity of the solution as follow:
Molarity = mole /Volume
Mole of C12H22O11 = 0.161 mole
Volume = 0.95L
Molarity = 0.161/ 0.95
Molarity = 0.169M