208k views
9 votes
Y={2x-1)(x+4)(2x-3)(x-1)

1 Answer

2 votes

Answer:

Y =4x^4 + 4x^3 − 37x^2 + 41x −12

Explanation:

Y = (2x - 1 ) (x + 4) (2x - 3) (x - 1)

Using commutative property we can re-arrange RHS,

Y= (2x - 1) (2x - 3) (x + 4) (x - 1)

Using the property

[(x+a) (x+b) = x^2 + (a+b)*x +ab],

Y =

[(2x)^2 + (-1 - 3)*2x + (-1 )*(-3)] [x^2 + (4 - 1)*x + 4*(-1)]

From here onwards I would recommend u to do the calculation by your own bc I might have made mistakes

in the steps but I got right but still just check yourself if u copy all the steps as it is

Y = (4x^2 -8x + 3) (x^2 + 3x -4)

Y = 4x^4 + 12x^3 - 16x^2 -8x^3 -24x^2 + 32x + 3x^2 + 9x - 12

Y = 4x^4 + 4x^3 -37x^2 + 41x - 12

Here I got the answer right so my calculations will also might be right

I checked my answer if it's right using an app called "MathPapa" and it's a great app to solve algebra questions like urs. The screenshot of the answer using this app is here on the top. This is the longest question I have solved for anyone, bye and have a nice day ahead!

Y={2x-1)(x+4)(2x-3)(x-1)-example-1
User Fligant
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories