Answer:
Explanation:
1) Construct a probability tree (check the attachment).
1.1) Change the given items/values into fractions. In this case, there are 3 entrees, each with a probability of
because the probability of selecting a hamburger (an example that could be applied to other options too) is 1 out of the 3 options. Likewise is the case with sides and drinks; the probability of selecting fries (or vegetable) out of the two options is
, and the probability of selecting milk (or juice) out of the two options is
.