Question

How many grams of HF are needed to react with 3.0 moles of Sn?*

10 points
→ SnF2 + H2
Sn + 2 HF
O 309
O 609
120g
2409

Answer 1

Answer: 120 grams of HF are needed to react with 3.0 moles of Sn

Step-by-step explanation:

The balanced chemical equation is :

`SnF_2+H_2\rightarrow Sn+2HF`

According to stoichiometry:

1 mole of
`Sn` reacts with 2 moles of HF

Thus 3.0 moles of Sn will react =
`(2)/(1)* 3.0=6.0` moles of HF

Mass of
`HF=moles* {\text {molar mass}}=6.0mol* 20.01g/mol=120g`

Thus 120 grams of HF are needed to react with 3.0 moles of Sn