Question

Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the computer. Together they had $696 more than they need to pay. What is the price of the computer?

Answer 1

The price of the computer is $1,152

Explanation:

Let the price of the computer be $x

The first boy boy had 7/8 of this amount, the amount he has is thus 7/8 × $x = 7x/8

The second boy had 5/6 of what the first boy had. The amount of money he has is thus 5/6 × 7x/8 = 35x/48

Now, the addition of what they have is $696 more than what they need to pay. This amount is x+ 696

Mathematically, this can be represented as;

7x/8 + 35x/48 = x + 696

(42x + 35x)/48 = (x + 696)

77x/48 = (x + 696)

77x = 48(x + 696)

77x = 48x + 33408

77x - 48x = 33408

29x = 33, 408

x = 33,408/29

x = $1,152