Question

Why does 40.0 g of NaOH added to 1.00 L of water not make a 1.00 M NaOH solution

Answer 1

When 40.0 g of NaOH is added to 1.00 L of water, it does not make a 1.00 M NaOH solution because the molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters.

Step-by-step explanation:

When 40.0 g of NaOH is added to 1.00 L of water, it does not make a 1.00 M NaOH solution because the molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters.

To make a 1.00 M NaOH solution, we need to know the number of moles of NaOH and the volume of the solution in which it is dissolved. In this case, we are given the mass of NaOH (40.0 g) but not the volume of the solution. Without the volume, we cannot calculate the molarity.

To determine the molarity, we need to know either the volume of the solution or the number of moles of NaOH added to the solution.

Answer 2

First weigh 40g NaOH in breaker and dissolve with 400 to 500 mL with purified water. Then allow to cool the solution and volume upto 1000 mL with purified water. Then standardization your Solution.

Step-by-step explanation:

molarity = no. of moles of solute / 1 liter .

* one moles of sodium hydroxide = 40 gm of sodium hydroxide.

so we can said ; if want prepare 1 molar NaOH solution then we need 40 gm NaOH dissolve in one liter of water so it became one 1 molar NaOH solution.