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How much heat (in Joules) will be needed to vaporize 18.015 grams of liquid water at 100°C?

User Soooooot
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1 Answer

1 vote

Answer:

40659.855 J

Step-by-step explanation:

From the question given above, we obtained the following:

Mass (m) = 18.015g

Heat of vaporisation (ΔHv) = 2257 J/g

Heat (Q) =?

The heat required to vaporise the water can be calculated as follow:

Q = mΔHv

Q = 18.015 x 2257

Q = 40659.855 J

Therefore, the heat required to vaporise the water is 40659.855 J

User Amartine
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