Question

Question 1. A satellite’s velocity is 30,000m/s. After 60 seconds, it’s velocity slows to 15,000 m/s. What is the satellite’s acceleration?

Question 2. A speed boat increases its speed from 42 m/s to 88m/s in a 4 second period. What is the acceleration during this period?

Answer 1

Step-by-step explanation:

1.

Initial speed of satellite is 30,000 m/s

Final speed of satellite is 15000 m/s

Time taken by the satellite to reach final speed is 60 s

The satellite’s acceleration is equal to the change in velocity divided by time taken. So,

`a=(v-u)/(t)\\\\a=(15000 -30000)/(60)\\\\a=-250\ m/s^2`

2.

Initial speed of a boat is 42 m/s

Final speed of a boat is 88 m/s

Time taken is 4 s

The acceleration of boat during this period is :

`a=(v-u)/(t)\\\\a=(88-42)/(4)\\\\a=11.5\ m/s^2`