Answer:
0.333 M
Step-by-step explanation:
Step 1: Write the balanced equation
2 HCl(aq) + Mg(OH)₂(aq) = MgCl₂(aq) + 2 H₂O(l)
Step 2: Calculate the reacting moles of Mg(OH)₂
25.00 mL of a 0.200 M magnesium hydroxide react. The reacting moles of Mg(OH)₂ are:
![25.00 * 10^(-3) L * (0.200mol)/(L) = 5.00 * 10^(-3) mol](https://img.qammunity.org/2021/formulas/chemistry/college/okvoqjyh4wezok7ghxw219nkvams9mhk5p.png)
Step 3: Calculate the reacting moles of HCl
The molar ratio of HCl(aq) to Mg(OH)₂ is 2:1. The reacting moles of HCl are:
![5.00 * 10^(-3) molMg(OH)_2 * (2mol)/(1molMg(OH)_2) =1.00 * 10^(-2)molHCl](https://img.qammunity.org/2021/formulas/chemistry/college/6enmx3zguhj6y5eowdbxowldttxe4ynct4.png)
Step 4: Calculate the molarity of HCl
![(1.00 * 10^(-2)mol)/(30.00 * 10^(-3)L) = 0.333 M](https://img.qammunity.org/2021/formulas/chemistry/college/43siku8azyjb643x8pal1mozynvhmc034j.png)