Question

A meat baster consists of a squeeze bulb attached to a plastic tube. When the bulb is squeezed and released, with the open end of the tube under the surface of the basting sauce, the sauce rises in the tube to a distance h, as the drawing shows. Using 1.013 × 105 Pa for the atmospheric pressure and 1490 kg/m3 for the density of the sauce, find the absolute pressure PB in the bulb when the distance h is (a) 0.15 m and (b) 0.10 m.

Answer 1

Answer:
`P_(bulb)=99.11\ kPa`

Step-by-step explanation:

Given

When the bulb is squeezed then liquid level rises to height h i.e. pressure decreases inside the bulb which causes rises in the tube

for common elevation i.e. at liquid level pressure must be equal therefore

`P_(bulb)+\rho gh=P_(atm)`

`P_(bulb)=1.013* 10^5-1490* 9.8* h`

for
`h=0.15\ m`

`P_(bulb)=1.013* 10^5-1490* 9.8* 0.15`

`P_(bulb)=101.3* 10^3-2.1903* 10^3`

`P_(bulb)=99.11\ kPa`

for
`h=0.1\ m`

`P_(bulb)=101.3* 10^3-1.4602* 10^3`

`P_(bulb)=99.83\ kPa`