Question

Antifreeze is used in car engines. It is produced by a local manufacturer, but they’ve run out of an ingredient: ethane (C2H6). As a junior scientist, you know you can produce ethane by reacting sulfuric acid with diethyl zinc gas. The local manufacturer will pay $1.25 per gram of ethane you produce. If you have 45.00 mL of 8.00 M H2SO4 and 30.00 mL of Zn(CH3CH2)2, what is the maximum amount of money you can make?

Answer 1

Maximum amount of money = $21.95

Step-by-step explanation:

Required reaction:

H2SO4 + Zn(CH3CH2)2 -------------> 2 C2H6 + ZnSO4

No.of moles of H2SO4= (45 x 10-3 L) x (8 M) = 0.360 mol

No.of moles of Zn(CH3CH2)2 = (30 x 1.205) / (123.50 g/mol) = 0.2927 mol

Here H2SO4 is in excess amount and Zn(CH3CH2)2is the limiting reagent.

Hence, Maximum no.of moles of ethane that can be produced = 2 * 0.2927 mol = 0.484 mol

Hence, Mass of ethane that can be produced = 0.484 mol x 30 g/mol = 17.56 g

Therefore,Maximum amount of money that you can make :

Maximum amount of money = (17.56 g) x ($1.25 /g)

Maximum amount of money = $21.95