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CaCO3(s) + HCl → CaCl2(s) + CO2(g) + H2O(g)

A large amount of heat is generated by this reaction, so the water produced from the reaction is
usually driven off as steam. Some liquid water may remain, however, and it may dissolve some of the
desired calcium chloride. What is the percent yield if 155 g of calcium carbonate is treated with 250 g
of anhydrous hydrogen chloride and only 142 g of CaCl2 is obtained?

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HELP PLEASE I have the same question but have no clue what the answer is
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