Question

Select the correct answer.

What is the solution to this system of equations?
x-2y = 15
2x+4y=-18
OA. x = 1, y=-6
OB. X= 1, y=-7
ОС. Х 3, y= -6
OD. x= 3, y=-7
Reset
Next

Answer 1

O C. x = 3, y = -6

Explanation:

• x - 2y = 15
• 2x + 4y = -18

Take Equation 1 and equate to x.

• x - 2y = 15
• x = 2y + 15

Now, substitute in Equation 2.

• 2x + 4y = -18
• 2(2y + 15) + 4y = -18
• 4y + 30 + 4y = -18
• 8y = -48
• y = -6
• x = 15 + 2(-6)
• x = 3
• Option C

Answer 2

C) x = 3, y = -6

Explanation:

`\textsf{Equation 1}:x-2y=15`

`\textsf{Equation 2}:2x+4y=-18`

Rewrite Equation 1 to make x the subject:

`\implies x=15+2y`

Substitute into Equation 2 and solve for y:

`\implies 2(15+2y)+4y=-18`

`\implies 30+4y+4y=-18`

`\implies 8y=-48`

`\implies y=-6`

Substitute found value of y into Equation 1 and solve for x:

`\implies x-2(-6)=15`

`\implies x+12=15`

`\implies x=3`

Therefore, the solution to the system of equations is:

x = 3, y = -6