Register
Find the equation of the line that is perpendicular to y = – 1 3 x + 2 and passes though the point (–5, 2) A) y = 3x + 13 B) y = 3x + 17 C) y = –3x + 13 D) y = –3x + 17
114k views
0 votes
Find the equation of the line that is perpendicular to y = – 1 3 x + 2 and passes though the point (–5, 2)

A) y = 3x + 13
B) y = 3x + 17
C) y = –3x + 13
D) y = –3x + 17

User Travis Clarke
by
4.7k points

2 Answers

7 votes

Answer:

B

Explanation:

User Vilijou
by
5.3k points
6 votes

Answer:

y = 3x + 17

Explanation:

User Patrick Q
by
5.5k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.7m questions

7.4m answers

Other Questions

Evaluate a + b when a = –16.2 and b = –11.4 A. –27.6 B. –4.8 C. 4.8 D. 27.6
What is the value of x? (-4) - x = 5
Can someone help me with 5??? ASAP?
1/7 + 3/14 equivalent fractions
185g in the ratio 2:3
Link Copied!