Answer:
You have to invest $5,020.71 to have $6,000 in 4 years 3 months at 4 1\5% annual interest, compounded monthly.
Explanation:
Let the principal be x
Amount = $6000
Time = 4 years 3 months =
![4 years +(3)/(12) years = 4.25 years](https://img.qammunity.org/2021/formulas/mathematics/high-school/wek6jdwddua47ra2wkir2fm97lzhd92eww.png)
Rate of interest =
![4 (1)/(5)\% = (21)/(5)\%](https://img.qammunity.org/2021/formulas/mathematics/high-school/loolthoqbzytxiqe1qin4ihw09mk6dwnr0.png)
No. of compounds per year = 12
Formula:
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qsdew1qblb5nrvw0u09d20h4jv0t1cxr0s.png)
![6000=P(1+(21)/(500 * 12))^(12 * 4.25)](https://img.qammunity.org/2021/formulas/mathematics/high-school/fity33rxll1m49m3ua5sldlyafdqfr9oaz.png)
=P
P=$5,020.71
Hence You have to invest $5,020.71 to have $6,000 in 4 years 3 months at 4 1\5% annual interest, compounded monthly.