Question

Question 63 of 70 1.5 Points When 2-bromo-2-methylbutane is treated with a base, a mixture of 2-methyl-2-butene and 2-methyl-1-butene is produced. When potassium hydroxide is the base, 2-methyl-1-butene accounts for 45% of the product mixture. However, when potassium tert-butoxide is the base, 2-methyl-1-butene accounts for 70% of the product mixture. What percent of 2-methyl-1-butene would be in the mixture if potassium propoxide were the base

Answer 1

Answer: between 45% and 70%

Step-by-step explanation:

taking this step by step, let us analyze this question carefully.

From the original image in the question, as can be seen in the second uploaded image, we observe that;

potassium hydroxide having being less bulky produces about 45% of 2-methyl-butane whereas potassium tert-butoxide having being bulky produces 70% of this product.

Given the potassium propoxide as the base and intermediate to that of potassium hydroxide and potassium tert-butoxide, it produces 2-methyl-1-butane in between 45% to 70%.

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