Question

Calculate the period of oscillation of a pendulum with a small amplitude whose length is 2.5 meters.

Answer 1

Period is 1.57 seconds

Step-by-step explanation:

From simple harmonic motion :

`period = 2\pi \sqrt{ (l)/(g) }`

T = 2π√(2.5÷10)

T = 0.25 × 2π

T = 1.57 s