Answer:
Explanation:
The correct answer is (C).
Because the sample sizes are less than 10% of their respective population sizes, the standard deviation of the difference in sample means is approximately \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}} = \sqrt{\frac{12.8^2}{30}+\frac{5.2^2}{40}} \approx 2.912
n
1
s
1
2
+
n
2
s
2
2
=
30
12.8
2
+
40
5.2
2
≈2.912 minutes.