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An air conditioner operating between 93°F and 70°F is rated at 4000 Btu/h cooling capacity. Its coefficient of performance is 27% of that of a Carnot refrigerator operating between the same two temperatures. What horsepower is required of the air conditioner motor? (Halliday, 05/2018, p. 606) Halliday, D., Resnick, R., Walker, J. (05/2018). Fundamentals of Physics, 11th Edition [VitalSource Bookshelf version]. Retrieved from vbk://9781119306856 Always check citation for accuracy before use.

User Wrosecrans
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1 Answer

1 vote

Answer:
P_(in)=0.25\ Hp

Step-by-step explanation:

Given

Operating temperatures are


T_L=70^(\circ)F\approx 294.261\ K


T_H=93^(\circ)F\approx 307\ K


COP is
27\% of Carnot refrigerator


COP_(carnot)=(T_L)/(T_H-T_L)


COP_(carnot)=(294.261)/(307-294.261)


COP_(carnot)=(294.261)/(12.74)


COP_(carnot)=23.09\approx 23.1

actual
COP=0.27 * COP_(carnot)


COP_(actual)=6.237

Also,
COP=\frac{\text{Desired effect}}{\text{Power in}}


6.237=(4000)/(P_(in))


P_(in)=(4000)/(6.237)=641.33\ Btu/h


P_(in)=0.25\ Hp

User Mszymborski
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