Question

How do you solve this???
`(3)/(2)r = -1`

Answer 1

`{ \qquad{ {{ \tt{ - (2)/(3) }}}}} \\ \\`

Given equation,

`\\ { \longrightarrow \qquad{ {{ \tt{ (3)/(2) \: r = -1 }}}}} \\ \\`

Multiplying both sides by
`\sf (1)/(3)` we get :

`\\ { \longrightarrow \qquad{ {{ \tt{ (1)/(3) * (3)/(2)r = (1)/(3) * -1 }}}}} \\ \\`

`{ \longrightarrow \qquad{ {{ \tt{ (1)/( \cancel3) * ( \cancel3)/(2)r = - ( 1)/( 3) }}}}} \\ \\`

`{ \longrightarrow \qquad{ {{ \tt{ (1)/(2)r = - (1)/(3) }}}}} \\ \\`

Now, Multiplying both sides by 2 we get :

`\\ { \longrightarrow \qquad{ {{ \tt{ 2 * (1)/(2)r = 2 * - (1)/(3) }}}}} \\ \\`

`{ \longrightarrow \qquad{ {{ \tt{ \cancel2 * (1)/( \cancel2)r = - (2)/(3) }}}}} \\ \\`

`{ \longrightarrow \qquad{ {{ \tt{ {1}r = - (2)/(3) }}}}} \\ \\`

`{ \longrightarrow \qquad{ \frak {{ \pmb{ r = - (2)/(3) }}}}} \\ \\`

Answer 2

• 
  `\boxed{\sf{r=-(2)/(3) }}`

Explanation:

Isolate the term of r, from one side of the equation.

3/2r=-1

First, multiply by 2 from both sides.

2*3/2r=2(-1)

Solve.

3r=-2

Then, you divide by 3 from both sides.

3r/3=-2/3

Solve.

Divide the numbers from left to right.

r=-2/3

-2/3=-0.66

`\Longrightarrow: \boxed{\sf{r=-(2)/(3)}}`

• Therefore, the correct answer is r=-2/3.

I hope this helps! Let me know if you have any questions.