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Laser light of wavelength 510 nm is traveling in air andshines at normal incidence onto the flat end of a transparent plasticrod that has n = 1.30. The end of the rod has a thin coating ofa transparent material that has refractive index 1.65. Whatis theminimum (nonzero) thickness of the coating (a) for which thereis maximum transmission of the light into the rod; (b) for whichtransmission into the rod is minimized?

User Suslik
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1 Answer

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Answer:

a

The thickness is
t_1 = 155nm

b

The thickness is
t_2 =77.3 nm

Step-by-step explanation:

From the question we are told that

The wavelength of the laser light is
\lambda = 510 nm = 510*10^(-9) m

The refractive index of the plastic rod is
n = 1.30

The refractive index of the transparent coating is
n__(T)} = 1.65

For maximum transmission of light into the rod the reflection would be minimum and this minimum reflection is mathematically represented as


2 t_1 = m (\lambda )/(n___(T))}

Where m is the order of interference which is equal to 1

t is the thickness

Substituting values


2 t_1 = (510*10^(-9))/(1.65)


t_1 = (510*10^(-9))/( 2 * 1.65)


t_1 = 155nm

For minimum transmission of light into the rod the reflection would be maximum and this maximum reflection is mathematically represented as


2t_2 = [ m + (1)/(2) ] (\lambda )/(n__(T))}

Where m = 0 this because the transmission of light is minimum

Substituting values


2t_2 = [ 0 + (1)/(2) ] (510 *10^(-9) )/(1.65)


t_2 = [ 0 + (1)/(2) ] (510 *10^(-9) )/( 2 * 1.65)


t_2 =77.3 nm

User Morganis
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