Question

Given the point (3,-6) and a slope of 1/3 what is the equation

Answer 1

y=1/3x-7

Explanation:

Since we are given a point and a slope, we can use the point slope formula

`y-y_(1) =m(x-x_(1))`

where m is the slope, y1 is the y coordinate of the point is x1 is the x coordinate of the point

We know m, or the slope is 1/3.

We are given the point (3, -6). Therefore, our y coordinate is -6, and the x coordinate is 3.

So, we have m is 1/3, y1 is -6 and x1 is 3

y- -6=1/3(x-3)

y+6=1/3(x-3)

To find the equation in point slope form: y=mx+b, we need to get y by itself.

First, distribute the 1/3

y+6= 1/3*x + 1/3*-3

y+6=1/3x-1

Subtract 6 from both sides

y+6-6=1/3x-1-6

y=1/3x-7

Answer 2

y= 1/3x-7

Explanation:

To find the linear equation you have to plug in the values into slope-intercept form:

`y-y_(1) =m(x-x_(1))`

y- (-6) = 1/3 (x-3)

Then simplify the expression:

y+ 6 = 1/3x - 1

y = 1/3x -- 7