Answer: The final pressure inside a scuba tank is 30.5 atm
Step-by-step explanation:
To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
![(P_1)/(T_1)=(P_2)/(T_2)](https://img.qammunity.org/2021/formulas/chemistry/high-school/djlfnlyy5uburbey6vx6jwso32aea28a9w.png)
where,
are the initial pressure and temperature of the gas.
are the final pressure and temperature of the gas.
We are given:
![P_1=130.4\\T_1=1.00* 10^3^0C=(1000+273)K=1273K\\P_2=?\\T_2=25.0^0C=(25.0+273)K=298K](https://img.qammunity.org/2021/formulas/chemistry/high-school/tbm640gm8v53vj0alt25xfhlqq2l153xwo.png)
Putting values in above equation, we get:
![(130.4)/(1273K)=(P_2)/(298)\\\\P_2=30.5atm](https://img.qammunity.org/2021/formulas/chemistry/high-school/c6uz1r5oe5o31bud96o3eq4a43kivdgy7c.png)
Hence, the final pressure inside a scuba tank is 30.5 atm