Answer:
100°C
Step-by-step explanation:
The following were obtained from the question:
Initial temperature (T1) = 298 K
Initial pressure (P1) = 32.5 Psi
Final pressure (P2) = 40.68 Psi
Final temperature (T2) =..?
The final temperature can be obtained as follow:
P1/T1 = P2/T2
32.5/298 = 40.68/T2
Cross multiply to express in linear form
32.5 x T2 = 298 x 40.68
Divide both side by 32.5
T2 = (298 x 40.68) /32.5
T2 = 373K
Next, we shall convert 373K to celsius.
This is illustrated below:
T(°C) = T(K) – 273
T(K) = 373
T(°C) = 373 – 273
T(°C) = 100°C
Therefore, the temperature of the air inside the tire at 40.68 Psi is 100°C