Question

The sum of three numbers is 13. The sum of twice the first number, 5 times the second number, and 6 times the third number is 67. The difference between 5 times the first number and the second number is 7. Find the three numbers

Answer 1

Answer: 2,3,8

Explanation:

if,

x+y+z=13

2x+5y+6z=67

5x-y=7

Solve [x+y+z=13 2x+5y+6z=67] to find: -3x+z=2 and keep

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x+y+z=13

5x-y=7

6x+z=20 and -3x+z=2

z=8

x=2

y=3